x^2-4x+17=

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Solution for x^2-4x+17= equation:


Simplifying
x2 + -4x + 17 = 0

Reorder the terms:
17 + -4x + x2 = 0

Solving
17 + -4x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-17' to each side of the equation.
17 + -4x + -17 + x2 = 0 + -17

Reorder the terms:
17 + -17 + -4x + x2 = 0 + -17

Combine like terms: 17 + -17 = 0
0 + -4x + x2 = 0 + -17
-4x + x2 = 0 + -17

Combine like terms: 0 + -17 = -17
-4x + x2 = -17

The x term is -4x.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4x + 4 + x2 = -17 + 4

Reorder the terms:
4 + -4x + x2 = -17 + 4

Combine like terms: -17 + 4 = -13
4 + -4x + x2 = -13

Factor a perfect square on the left side:
(x + -2)(x + -2) = -13

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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